1s2 2s2 2p6 3s2 3p2: Phosphorous: 1s2 2s2 2p6 3s2 3p3: Hydrogen: 1s1: Helium: 1s2: Lithium: 1s2 2s1: Boron: 1s2 2s2 2p1: Beryllium: 1s2 2s2: Oxygen: 1s2 2s2 2p4: Fluorine: 1s2 2s2 2p5: Neon: 1s2 2s2 2p6: Sodium: 1s2 2s2 2p6 3s1: Magnesium: 1s2 2s2 2p6 3s2: Aluminum: 1s2 2s2 2p6 3s2 3p1: Sulfur: 1s2 2s2 2p6 3s2 3p4: Chlorine: 1s2 2s2 2p6 3s2 3p5 ...

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Para que un átomo sea estable debe tener todos sus orbitales llenos (cada orbital con dos electrones, uno de espín +1/2 y otro de espín -1/2) Por ejemplo, el oxígeno, que tiene configuración electrónica 1s², 2s², 2p4, debe llegar a la configuración 1s2, 2s2, 2p6 con la cual los niveles 1 y 2 estarían llenos.

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Where are the six electrons for carbon located????? 6 C 1s2 2s2 2p2 Maximum number in s sublevel is 2 electron p sublevel is 6 electrons d sublevel is 10 electrons f sublevel is 14 electrons Quantum Wave Mechanical Model (Schrodinger) type of subshellsthwithin level 3 2 d p s f d p s 4 s n p orbitals are within subshells principal quantum 1 s ...

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下列是几种原子的基态电子排布,电负性最大的原子是 A.1s2 2s2 2p4 B.1s2 2s2 2p6 3s2 3p2 1年前 3个回答 如果说O(1s2 2s2 2p4)被称为是氧的电子组态(electron configuration)的话,那么O(2

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b) 1s2 2s2 2p4 e 6 elétrons. c) 2s2 2p4 e 6 elétrons. d) 2s2 2p4 e 8 elétrons. 12 O para magnetismo \u2013 propriedade de ser atraído por um campo magnético \u2013 provém dos spins dos elétrons e ocorre em substâncias constituídas por íons ou átomos com elétrons desemparelhados.

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Nitrógeno 7; 1s2 2s2 2p3 oxígeno 8; 1s2 2s2 2p4 Flúor 9; 1s2 2s2 2p5 Neón 10; 1s2 2s2 2p6 Sodio 11; 1s2 2s2 2p6 3s1 Magnesio 12; 1s2 2s2 2p6 3s2 Aluminio 13; 1s2 2s2 2p6 3s2 3p1 Silicio 14; 1s2 2s2 2p6 3s2 3p2 fósforo 15; 1s2 2s2 2p6 3s2 3p3 Azufre 16; 1s2 2s2 2p6 3s2 3p4 Cloro 17; 1s2 2s2 2p6 3s2 3p5

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1s2 2s2 2p4 or [He] 2s2 2p4 1s2 2s2 2p5 or [He] 2s2 2p5 (Z = 10) : 1s2 2s2 2p6 or [He] 2s2 2p6 191 (IONe has stable configuration since three 2P orbitals are fully filled) or [He] 2s2 2px? 2py? 2pž2. Now 2P sub-shell cannot accomodate any more electron. IONe is inert gas. The next electron will go to the third shell with n = 3 i.e. in 3s. IINa ...

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Diagram Tingkat Energi Molekul CO Konfigurasi elektron Atom 6C = 1s2 2s2 2p2 Konfigurasi elektron Atom 8O = 1s2 2s2 2p4 Orbital atom C Orbital molekul CO Orbital atom O 6*2p 2*2p 2*2p. 2p 2p 12p 12p 52pz. 4*2s. Energi. 2s 2s 32s. 2*1s. 1s 1s 11s

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Каким ионам соответствует электронная формула 1s2 2s2 2p4 александр Гребенюк Профи (502), на голосовании

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N: 1s2 2s2 2p3 = [He] 2s2 2p3 N3–: 1s2 2s2 2p6 = [He] 2s2 2p6 = [Ne] O: 1s2 2s2 2p4 = [He] 2s2 2p4 O2–: 1s2 2s2 2p6 = [He] 2s2 2p6 = [Ne] F: 1s2 2s2 2p5 = [He] 2s2 2p5 F–: 1s2 2s2 2p6 = [He] 2s2 2p6 = [Ne] * Example 4: Electron config. and NG Abb. Cl- F- Ca2+ Na+ * Ionic Radii or size Atoms shrink when an electron is removed to form a ...

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1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d5 5s1---> ô 42, chu kì 5, nhóm VIB. 2, O (z = 8): 1s2 2s2 2p4 ---> ô 8, chu kì 2, nhóm VIA. Mg( z= 12): 1s2 2s2 2p6 3s2---> ô 12, chu kì 3, nhóm IIA. P(z=15) 1s2 2s2 2p6 3s2 3p3---> ô 15, chu kì 3, nhóm VA. Ca (z=20) như câu 1. Ar(z=18) 1s2 2s2 2p6 3s2 3p6---> ô 18, chu kì 3, nhóm VIIIIA

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(Au brouillon -> petit schéma pour s'aider) Configuration électronique : 1s2 2s2 2p4 (somme des électrons = 8)

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It helps to predict the values of all the four quantum number of any electron. 3) Which rule is violated in the electronic configuration? 1S0 2S2 2P4. Ans: Aufbau principle is violated in this electronic configuration because according to Aufbau principle, Electron enters into orbital of lower energy.

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